Question 616161: Three fair dice are tossed once. What is the probability that the faces show three consecutive integers? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Three fair dice are tossed once. What is the probability that the faces show three consecutive integers?
----
# of ways to succeed:
There are 3 consecutive sequences possible.
There are 3*2*1 = 6 ways to achieve one of those sequences with the 3 dice.
----
# of ways to succeed = 3*6 = 18
====
# of possible outcomes when you toss 3 dice = 6^3 = 216
---
P(3 consecutive integers) = 18/216
===================
cheers,
Stan H.
===============