SOLUTION: show that the area of a square is half the product of its diagonals

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Question 592377: show that the area of a square is half the product of its diagonals
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
From the pythagorean theorem, d^2 = s^2 + s^2 = 2s^2

So d^2 = 2s^2

The area of a square with side length 's' is A = s^2

So you must take half of 2s^2 to get s^2

Therefore, the area is (d^2)/2