SOLUTION: What is the missing length in a box with 1480 suface area and 18 and 10 as two of the side lengths

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Question 552027: What is the missing length in a box with 1480 suface area and 18 and 10 as two of the side lengths
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
What is the missing length in a box with 1480 surface area and 18 and 10 as two of the side lengths
:
Formula for surface area of a box: S.A. = 2(L*W) + 2(L*H) + 2(W*H)
Let L = 18
Let W = 10
Let H = the unknown value
Given the surface area as 1480:
:
2(18*10) + 2(18H) + 2(10h) = 1480
Simplify, divide thru by 2
(18*10) + (18H) + (10h) = 740
180 + 28H = 740
28H = 740 - 180
28H = 560
H = 560%2F28
H = 20 units is the missing length
:
:
Check the solution in the original S.A. equation.