SOLUTION: What's the area of a triangle whose vertices have coordinates (-1,2), (-1,-1), and (-6,2)

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Question 52121This question is from textbook
: What's the area of a triangle whose vertices have coordinates (-1,2), (-1,-1), and (-6,2) This question is from textbook

Found 2 solutions by checkley71, josmiceli:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
ONE SIDE IS 2-(-1)=3 AND ANOTHER IS -1-(-6)=5 SO THE AREA IS BH/2 OR 3*5/2=15/2=7.5

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
A = 1/2*bh
(-1,2),(-1,-1),(-6,2)
b+=+sqrt%28%28x2+-+x1%29%5E2+%2B+%28y2+-+y1%29%5E2%29
b+=+sqrt%28%28%28-1%29+-+%28-6%29%29%5E2+%2B+%282+-+2%29%5E2%29
b+=+sqrt%285%5E2+%2B+0%5E2%29
b+=+5
h+=+abs%28-1+-+2%29+
h+=+3
A+=+1%2F2%2A%285%2A3%29
A+=+7.5