SOLUTION: What is the area of the net that folds to make this square pyramid? Perpendicular Height = 8cm Base = 9cm

Algebra ->  Surface-area -> SOLUTION: What is the area of the net that folds to make this square pyramid? Perpendicular Height = 8cm Base = 9cm      Log On


   



Question 479163: What is the area of the net that folds to make this square pyramid?
Perpendicular Height = 8cm
Base = 9cm

Answer by ccs2011(207) About Me  (Show Source):
You can put this solution on YOUR website!
Basically they are asking for the surface area of this square pyramid.
SA+=+B+%2B+%28P%2Al%29%2F2
where B is area of base, P is perimeter of base, l is slant height.
Area of base = 9*9 = 81
Perimeter of base = 4*9 = 36
Slant height can be found using Pythagorean theorem: a%5E2+%2Bb%5E2=c%5E2
where slant height is the hypotenuse, the vertical height is one leg, and half the length of a side of base is other leg.
8%5E2+%2B+4.5%5E2+=+c%5E2
64+%2B+20.25+=+c%5E2
84.25+=+c%5E2
9.179+=+c
Now compute surface area:
SA+=+81+%2B%2836%2A9.179%29%2F2+=+246.22