SOLUTION: The lenght of a rectangle is 2 in. more than twice its width.if the perimeter of the rectangle is 34 in. find the dimensions of the rectangle.

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Question 45168: The lenght of a rectangle is 2 in. more than twice its width.if the perimeter of the rectangle is 34 in. find the dimensions of the rectangle.
Answer by aaaaaaaa(138) About Me  (Show Source):
You can put this solution on YOUR website!
Some variables I'll use:
l = length
w = width
p = perimeter
First, we have that
l+=+2w+%2B+2
And the formula for a perimeter calculation, in general, is l+l+w+w, or:
p+=+2l+%2B+2w
Substituting 34 for p:
34+=+2l+%2B+2w
Substituting 2w + 2 for l:
34+=+2%282w+%2B+2%29+%2B+2w

And now we solve for the width:
34+=+4w+%2B+4+%2B+2w
34+=+6w+%2B+4
30+=+6w
5+=+w
If l is 2w+2, substituting w for 5 gives us:
l+=+2w+%2B+2+=+2%2A5+%2B+2+=+10+%2B+2+=+12
Therefore, the length is 12 inches and the width, 5 inches.