SOLUTION: what is the surface area of cylinder with a 4 feet radius and 50 feet long

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Question 426870: what is the surface area of cylinder with a 4 feet radius and 50 feet long
Answer by mananth(16946) About Me  (Show Source):
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The surface area of cylinder = 2 pir(r+l)
Radius = 4 feet
Length = 50 feet
The surface area of cylinder S = 2pi*4(4+50)
S=2*3.14 2*54
S=1357.34sq.feet