SOLUTION: The outside dimensions of a picture frame are 3 feet by 29 inches. If its inside dimensions are 1 2/3 feet by 22 inches, what is the area of the frame? I've tried to do length

Algebra ->  Surface-area -> SOLUTION: The outside dimensions of a picture frame are 3 feet by 29 inches. If its inside dimensions are 1 2/3 feet by 22 inches, what is the area of the frame? I've tried to do length       Log On


   

Question 381140: The outside dimensions of a picture frame are 3 feet by 29 inches. If its inside dimensions are 1 2/3 feet by 22 inches, what is the area of the frame?
I've tried to do length times width on both sizes but the answer is a multiple choice and none of the answers I've come up with are a choice. Here's what I've tried...outside-- 36 inches x 29 inches= 1044 inches or 87 feet
inside-- 20 inches x 22 inches= 440 inches or 36.66 feet
answer choices are A) 137.33 ft2 B) 616 in2 C) 144.67 ft2 D) 604 in2
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
you actually have found the answer , except for the final step

the inches of AREA that you have calculated are actually square inches (or in^2)

if you take the difference of your two calculations , you'll see the answer


FYI ... 144 in^2 = 1 ft^2