SOLUTION: a sprinkler is set in a corner of a rectangular lawn 10 ft by 25 ft. If the maximum distance the sprinkler can reacch is 10 ft --- what percent of the lawn will be watered from th
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-> SOLUTION: a sprinkler is set in a corner of a rectangular lawn 10 ft by 25 ft. If the maximum distance the sprinkler can reacch is 10 ft --- what percent of the lawn will be watered from th
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Question 353480: a sprinkler is set in a corner of a rectangular lawn 10 ft by 25 ft. If the maximum distance the sprinkler can reacch is 10 ft --- what percent of the lawn will be watered from this position?
i have A= 10 x 25 =250 A of circle 3.14 x 5^2 = 78.54
solution 79/250 = .316 which is 32%. I my answer correct Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! This is all good:
A= 10 x 25 =250 A of circle 3.14 x 5^2 = 78.54
.
However, since the sprinkler is placed on a corner, only 1/4 of the water will hit the lawn -- therefore:
area covered by sprinkler is 78.54(.25) = 19.63
.
Percent coverage:
19.63/250 = .079 or 7.9%
