SOLUTION: Sonya walked at a rate of 1/t+a mph for bt+ab hours. How far did she walk?

Algebra ->  Surface-area -> SOLUTION: Sonya walked at a rate of 1/t+a mph for bt+ab hours. How far did she walk?      Log On


   

Question 337900: Sonya walked at a rate of 1/t+a mph for bt+ab hours. How far did she walk?
Found 2 solutions by ankor@dixie-net.com, Earlsdon:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Sonya walked at a rate of 1/t+a mph for bt+ab hours.
How far did she walk?
Dist = rate * time, therefore
d = 1%2F%28t%2Ba%29 * bt + ab
Factor
d = 1%2F%28t%2Ba%29 * b(t + a)
Cancel (t+a)
d = b

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let's use the distance formula:d+=+rt where d = distance(miles), r = rate
(speed)(mph), and t =time(hours).
d+=+rt Substitute r+=+1%2F%28t%2Ba%29 and t+=+bt%2Bab
d+=+%281%2F%28t%2Ba%29%29%28bt%2Bab%29 In the second parentheses, factor out a b.
d+=+%281%2Fcross%28%28t%2Ba%29%29%29%28b%2Across%28%28t%2Ba%29%29%29 Cancel the common factor (t%2Ba) to leave you with:
highlight%28d+=+b%29