SOLUTION: what is the area of a hexagon with 4-inch side A = sq. in

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Question 307171: what is the area of a hexagon with 4-inch side
A = sq. in
Found 2 solutions by Alan3354, nyc_function:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Area of any polygon with n sides of length s =
A+=+ns%5E2%2Acot%28180%2Fn%29%2F4+=+6%2A16%2Acot%2830%29%2F4
A = 24cot(30)
A = 24sqrt(3)
Area =~ 41.57 sq inches
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It's a good idea to be able to work these things. In the case of a regular hexagon, it's 6 equilateral triangles.
But, this one formula covers ALL regular polygons, so I like it.

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a regular hexagon is found using A = [3(sqrt{3})]/2 * (t^2), where t is the measure of one side of the regular hexagon.
In the formula above, replace t with your 4 and simplify.
Can you finish now?