SOLUTION: please illustrate the figure..The diagonals of a rhombus are 10 and 24.
(a) Find a side of the rhombus
(b) find the altitude of the rhombus
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Surface-area
-> SOLUTION: please illustrate the figure..The diagonals of a rhombus are 10 and 24.
(a) Find a side of the rhombus
(b) find the altitude of the rhombus
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Question 29175: please illustrate the figure..The diagonals of a rhombus are 10 and 24.
(a) Find a side of the rhombus
(b) find the altitude of the rhombus
You can put this solution on YOUR website! SEE THE FOLLOWING EXAMPLE AND TRY TO UNDERSTAND THE EXPLANATION.
ANSWERS ARE
SIDE=SQUARE ROOT OF ((10/2)^2+(24/2)^2)=13
ALTITUDE = AREA/SIDE
AREA =(1/2)*D1*D2=10*24/2=120
ALTITUDE=120/13=9.2
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IN A RHOMBUS IF SIDE IS X WE HAVE
(D1/2)^2+(D2/2)^2=X^2...WHERE D1 AND D2 ARE DIAGONALS
IF D1=X = 6=AB=BC=CD=DA.....GIVEN.....THEN
(X/2)^2+(D2/2)^2=X^2...
(D2/2)^2=3X^2/4
D2/2=X*SQRT3/2
D2=X*SQRT3
SO EACH DIAGONAL IS X AND X*SQRT(3)
NOW X=6 SO
D1=6=AC AND D2 =6SQRT(3)=10.4 =BD
FIGURE IS GIVEN BELOW...DIMENSIONS ARE NOT THE SAME AS THOSE OF GIVEN RHOMBUS.
