SOLUTION: It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame? I dont understand w

Algebra ->  Surface-area -> SOLUTION: It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame? I dont understand w      Log On


   



Question 277623: It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame?
I dont understand where to start HELP?!?!

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame?
I dont understand where to start HELP?!?!
4feet = 48 inches
Outside area = 48*29= 1392 square inches
1 3/4 feet = 21 inches
Indise area = 21 *21 =441 sq. inches
Difference between the outer area and the inner area will give the area of the frame
1392-441=951 square inches