SOLUTION: find the dimensions of the rectangle meeting the specified conditions
the perimeter is 320 cm and the width is 20 cm less than the length
Algebra ->
Surface-area
-> SOLUTION: find the dimensions of the rectangle meeting the specified conditions
the perimeter is 320 cm and the width is 20 cm less than the length
Log On
Question 223776: find the dimensions of the rectangle meeting the specified conditions
the perimeter is 320 cm and the width is 20 cm less than the length Found 2 solutions by stanbon, drj:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the dimensions of the rectangle meeting the specified conditions
the perimeter is 320 cm and the width is 20 cm less than the length
----------------------
Perimeter = 2(L + W)
320 = 2(L + (L-20))
160 = 2L-20
2L = 180
L = 90 cm (length)
W = L-20 = 70 cm (width)
=========================
Cheers,
Stan H.
You can put this solution on YOUR website! Find the dimensions of the rectangle meeting the specified conditions
the perimeter is 320 cm and the width is 20 cm less than the length
Step 1. Let L be the length
Step 2. Let L-20 be the width since it's 20 cm less than the length
Step 3. Perimeter P means adding up all 4 sides of the rectangle.
Step 4. Then, P=L+L+L-20+L-20=320 since perimeter is 320 cm.
Cartoon (animation) form: For tutors: simplify_cartoon( L+L+L-20+L-20=320 )
If you have a website, here's a link to this solution.
DETAILED EXPLANATION
Look at . Added fractions or integers together It becomes . Look at . Moved to the right of expression It becomes . Look at . Removed extra sign in front of It becomes . Look at . Eliminated similar terms,,, replacing them with It becomes . Look at . Added fractions or integers together It becomes . Look at . Remove unneeded parentheses around factor It becomes . Look at . Moved these terms to the left It becomes . Look at . Added fractions or integers together It becomes . Look at . Removed extra sign in front of It becomes . Look at . Solved linear equation equivalent to 4*L-360 =0 It becomes . Result: This is an equation! Solutions: L=90.
Universal Simplifier and Solver
Done!
With and L-20=70}}}. Also which is a true statement.
Step 5. The dimensions are that the length is 90 cm and the width is 70 cm.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.