SOLUTION: Two sides of a rombus form a 120 degree angle. The length of each side is 6 in. How do you find the area of the rhombus. I would like to know the steps, please. I did not enter

Algebra ->  Surface-area -> SOLUTION: Two sides of a rombus form a 120 degree angle. The length of each side is 6 in. How do you find the area of the rhombus. I would like to know the steps, please. I did not enter       Log On


   



Question 203728: Two sides of a rombus form a 120 degree angle. The length of each side is 6 in. How do you find the area of the rhombus. I would like to know the steps, please. I did not enter textbook information as this is online and not from the textbook.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
If two angles are 120, then the other two must total 360-2%2A120 = 120
So each other angle is 60.
When you draw diagonals in a rhombus, they form right angles at their intersection. See this URL down near the bottom --> http://www.math-prof.com/Geom/Geom_Ch_22.asp
So, what we have after we draw in the diagonals, is 4 triangles. Each triangle is 30-60-90. And the hypotenuse is 6.
Using the properties of a 30-60-90 (see http://www.themathpage.com/aTrig/30-60-90-triangle.htm), you can get the length of the other two legs.
Once you have that info, finding the area is easy A+=+bh%2F2
Since you have 4 congruent triangles, the total area is 4 times the area of a single triangle