SOLUTION: Find the ratio of the area of a rectangle whose length is three times its width to the area of an isosceles right triangle whose LEGS are each equal to the width of the rectangle.
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-> SOLUTION: Find the ratio of the area of a rectangle whose length is three times its width to the area of an isosceles right triangle whose LEGS are each equal to the width of the rectangle.
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Question 190605: Find the ratio of the area of a rectangle whose length is three times its width to the area of an isosceles right triangle whose LEGS are each equal to the width of the rectangle. Must draw diagram and show work. Answer by solver91311(24713) (Show Source):
The area of the rectangle is the length times the width, so:
The base and the altitude are the same as the legs in an isosceles right triangle, so the area of this triangle is the measure of one of the legs times itself divided by 2:
The ratio of the two areas is:
Which makes perfectly good sense because, looking at the diagram you can see that the triangle is one-half of a square and it would take 3 of such squares to make the rectangle.
