SOLUTION: The top and bottom margins of a poster are each 6 cm and the side margins are each 4cm. If the area of printed material on the poster is fixed at 384cm^3, find the dimensions of th

Algebra ->  Surface-area -> SOLUTION: The top and bottom margins of a poster are each 6 cm and the side margins are each 4cm. If the area of printed material on the poster is fixed at 384cm^3, find the dimensions of th      Log On


   

Question 169776: The top and bottom margins of a poster are each 6 cm and the side margins are each 4cm. If the area of printed material on the poster is fixed at 384cm^3, find the dimensions of the poster with the smallest area?
Thankyou for your time.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The top and bottom margins of a poster are each 6 cm and the side margins are each 4cm. If the area of printed material on the poster is fixed at 384cm^2, find the dimensions of the poster with the smallest area?
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Assume the printed area is a square.
It's dimensions are each sqrt(384)
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If you include the margins the dimensions are as follows:
length = sqrt(384)+12cm
width = sqrt(384) + 8cm
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The total area of the poster is LW = 384 + 96 + 20sqrt(384)
= 480 + 20sqrt(384)
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The area of the margin is total area - printed material area
= 480 + 20sqrt(384) - 384 = 96+20sqrt(384) = 387.92 cm^2
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Cheers,
Stan H.