SOLUTION: ABCDEF is a regular hexagon, and PQR is an equilateral triangle. Find the ratio of the area of the triangle to the area of the hexagon. https://ibb.co/BtQsnFj

Algebra ->  Surface-area -> SOLUTION: ABCDEF is a regular hexagon, and PQR is an equilateral triangle. Find the ratio of the area of the triangle to the area of the hexagon. https://ibb.co/BtQsnFj      Log On


   



Question 1209089: ABCDEF is a regular hexagon, and PQR is an equilateral triangle. Find the ratio of the area of the triangle to the area of the hexagon.
https://ibb.co/BtQsnFj

Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
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ABCDEF is a regular hexagon, and PQR is an equilateral triangle.
Find the ratio of the area of the triangle to the area of the hexagon.
https://ibb.co/BtQsnFj
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Let r be the side of the hexagon ABCDEF.


Then the area of the hexagon is the area of 6 equilateral triangles with the side "r"

    area of the hexagon = 6%2Ar%5E2%2A%28sqrt%283%29%2F4%29.


Regarding the triangle PQR, its side is, OBVIOUSLY, arithmetic mean of r and 2r
(its side is the mid-line of the trapezoid CDEB).

So, the side of the triangle PQR is  a = %28r%2B2r%29%2F2 = 1.5r.


Then the area of the triangle PQR is  a%5E2%2A%28sqrt%283%29%2F4%29 = 1.5%5E2%2Ar%5E2%2A%28sqrt%283%29%2F4%29.


Thus the ratio of the area of the triangle to the area of the hexagon is

    1.5%5E2%2F6 = 2.25%2F6 = %282.25%2A4%29%2F%286%2A4%29 = 9%2F24 = 3%2F8.    ANSWER

Solved, with complete explanations.