SOLUTION: A rose garden is formed by joining a rectangle, and semi circle, as shown below. The rectangle is 20 feet long and 12 feet wide. Find the area of the garden. Use the value of 3.14

Algebra ->  Surface-area -> SOLUTION: A rose garden is formed by joining a rectangle, and semi circle, as shown below. The rectangle is 20 feet long and 12 feet wide. Find the area of the garden. Use the value of 3.14       Log On


   



Question 1203371: A rose garden is formed by joining a rectangle, and semi circle, as shown below. The rectangle is 20 feet long and 12 feet wide. Find the area of the garden. Use the value of 3.14 for pi, and do not round your answer. Be sure to include the correct unit and answer.
Found 3 solutions by ikleyn, josgarithmetic, math_tutor2020:
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
A rose garden is formed by joining a rectangle, and semi circle, as shown below.
The rectangle is 20 feet long and 12 feet wide. Find the area of the garden.
Use the value of 3.14 for pi, and do not round your answer.
Be sure to include the correct unit and answer.
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Are you serious, or your post is a kind of joke ?

If you are serious, you should provide a picture, or give a link to a picture, or, at least,
to say, using your own words, to which side of the rectangle the semi-circle is joined.


I am very surprised to see this message, which pretends to be a Math problem,
prepared so carelessly . . .


////////////////////////


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Usually,  parents  (a mother,  a father)  or relatives teach a young child to this basic rule from the early age.

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Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The description due to being without the needed picture, gives two possibilities.
Either the semicircle is at the rectangle's length or at the rectangle's width.

Area is either
20%2A12%2B%281%2F2%29pi%2A%2820%2F2%29%5E2
highlight%28240%2B50pi%29
Or
20%2A12%2B%281%2F2%29pi%2A%2812%2F2%29%5E2
highlight%28240%2B18pi%29
.

Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

It depends if the diagram is this


OR if it's this


If it's the 1st diagram, then the semicircular area is
(1/2)*pi*r^2 = (1/2)*pi*6^2 = 18pi square feet.
That approximates to 18pi = 18*3.14 = 56.52 square feet

Add that onto the rectangular area of 12*20 = 240 square feet.
240+56.52 = 296.52

The total area in the 1st figure is approximately 296.52 square feet.



If on the other hand the diagram was the 2nd one I've shown above, then:
semicircle area = (1/2)*pi*r^2 = (1/2)*pi*10^2 = 50pi = 50*3.14 = 157
rectangular area = 12*20 = 240

total approximate area = 240+157 = 397 square feet

Both involve 240, but the difference is the semicircular area.