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The description in the post is not clear enough to identify the areas of the interest by a unique way.
I will interpret the post as " to find the sum of the areas of the two lunes ".
For the meaning of the term " lune " in Geometry see this Wikipedia article
https://en.wikipedia.org/wiki/Lune_(geometry)
Solution
The diameter is d = (Pythagoras), or
d^2 = 20^2 + 21^2 = 841.
The area of the large upper-right semi-circle is therefore
= = .
From it, subtract the area of the right angled triangle with the legs 20 and 21; this area is = 210.
You will get the sum of areas of two segments of the large circle
segments_area = . (1)
The area of two smaller semi-circles is
= (2)
( ! same as the area of the large semi-circle !)
Finally, to find the area under the problem's question, you should subtract the area of two segments (1)
from the area of two small semicircles of (2).
You will get then the answer to the problem's question as 210 square units.
Solved.