SOLUTION: A closed rectangular container with a square base is to have a volume of 18000 inches^3 . The material of the top and bottom of the container will cost $2 per inch^2 , the material

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Question 1148825: A closed rectangular container with a square base is to have a volume of 18000 inches^3 . The material of the top and bottom of the container will cost $2 per inch^2 , the material for the sides will cost $3 per inch^2 . Find the dimensions of the container of least cost.
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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Let x be the length of the side of the base, and

let y be the height of the container.


Then the volume is  x%5E2%2Ay = 18000 cubic inches.


The cost of the material for two bases is  2%2Ax%5E2 dollars;

the cost of the material for four lateral sides is  4*3*x*y = 12xy dollars.


The problem requires us to minimize  2x%5E2+%2B+12xy%7D%7D++under+the+restriction+++%7B%7B%7Bx%5E2%2Ay = 18000.


Using the restriction formula, express  y = 18000%2Fx%5E2  and substitute it  into the total cost expression.


Then the cost takes the form  C(x) = 2x%5E2+%2B+12xy = 2x%5E2+%2B+%2812%2A18000%29%2Fx.


Thus the problem is just reduced to finding minimum of the function


    C(x) = 2x%5E2+%2B+216000%2Fx.


To find it minimum, take a derivative and equate it to zero.  It gives you the equation

    C'(x) = 4x+-+216000%2Fx%5E2 = 0,

which implies

    4x^3 = 216000,

     x^3 = 54000

     x = root%283%2C54000%29 = 30%2Aroot%283%2C2%29.


Then  y = 18000%2Fx%5E2 = 18000%2F%28900%2Aroot%283%2C4%29%29 = 20%2Froot%283%2C4%29.


ANSWER.  x= 30%2Aroot%283%2C2%29 = 37.798 inches (approximately)  and  y= 20%2Froot%283%2C4%29 = 12.6 inches (approximately).


PARTIAL CHECK.  x%5E2%2Ay = 37.798%5E2%2A12.6 = 18001 in^3.  The miserable difference is due to rounding.

Solved.