SOLUTION: The length of a rectangle is 8 cm mor than 3 times its width. the perimeter of the rectangle is 64 cm. A. What are the dimensions of the rectangle? B. What is the area of the rec

Algebra ->  Surface-area -> SOLUTION: The length of a rectangle is 8 cm mor than 3 times its width. the perimeter of the rectangle is 64 cm. A. What are the dimensions of the rectangle? B. What is the area of the rec      Log On


   



Question 112277: The length of a rectangle is 8 cm mor than 3 times its width. the perimeter of the rectangle is 64 cm.
A. What are the dimensions of the rectangle?
B. What is the area of the rectangle?

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
L=3W+8
PERIMETER=2L+2W
64=2(3W+8)+2W
64=6W+16+2W
64=8W+16
8W=64-16
8W=48
W=48/8
W=6 CM FOR THE WIDTH.
L=3*6+8
L=18+8
L=26 CM FOR THE LENGTH
PROOF
64=2*6+2*26
64=12+52
64=64
AREA=W*L
AREA=6*26
AREA=156 CM^2 ANSWER FOR THE AREA.