SOLUTION: find the area under the curve of f(x)= x^3-3x^2+2x+1 from x=0, to x=1
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-> SOLUTION: find the area under the curve of f(x)= x^3-3x^2+2x+1 from x=0, to x=1
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Question 1121335
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find the area under the curve of f(x)= x^3-3x^2+2x+1 from x=0, to x=1
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htmentor(1343)
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To find the area under f(x), we need to integrate f(x) from 0 to 1
The anti-derivative of f(x) = x^4/4 - x^3 + x^2 + x
Evaluating the definite integral we get
1/4 - 1 + 1 + 1 - 0 = 5/4 = 1.25