Let the square be ABCD. Side of the square = AB = PQ = 2OQ. Since triangle OBQ is a 30°,60°,90° triangle, its longer leg is times its shorter leg. We let its shorter leg BQ be x, then its longer leg OQ is . Since = OQ = PQ/2 = AB/2, BC = 2∙OQ = . OC = radius = 8 Using Pythagorean theorem on right triangle OQC OQ² + QC² = OC² Solve that and get So one side of the square is twice that, or 2x, which is = side of square. Therefore the area of the square is or Edwin