SOLUTION: Find the exact area enclosed between the curve y = sqrt(4 − x^2) and the line x+2=y. I have found the area simply by using the area of the quadrant of the circle minus th

Algebra ->  Surface-area -> SOLUTION: Find the exact area enclosed between the curve y = sqrt(4 − x^2) and the line x+2=y. I have found the area simply by using the area of the quadrant of the circle minus th      Log On


   



Question 1105621: Find the exact area enclosed between the curve y = sqrt(4 − x^2) and the line x+2=y.
I have found the area simply by using the area of the quadrant of the circle minus the area of the triangle to get an answer of pi-2.
I've tried to integrate but it didn't get the right answer, could you check my working or work it out for yourself?
There was too much to write so I took a photo of my working instead: https://imgur.com/a/ziZlG

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the exact area enclosed between the curve y = sqrt(4 - x^2) and the line x+2=y.
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The INT of sqrt(4 - x^2) is not correct.
INT%28sqrt%284-x%5E2%29%29+=+%28x%2Asqrt%284-x%5E2%29+%2B+4arcsin%28x%2F2%29%29%2F2
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The area is pi-2. It's negative because is left of the y-axis, so it's the abs(2-pi).