SOLUTION: A Norman window has the shape of a rectangle surmounted by a semicircle. If the perimeter of the window is 1512 centimeters and the length of the base of the window is 112 centimet

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Question 1098847: A Norman window has the shape of a rectangle surmounted by a semicircle. If the perimeter of the window is 1512 centimeters and the length of the base of the window is 112 centimeters, find the total area of the window.
area=cm^2


Thank you for the help!
Found 2 solutions by ankor@dixie-net.com, MathTherapy:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A Norman window has the shape of a rectangle surmounted by a semicircle.
If the perimeter of the window is 1512 centimeters and the length of the base of the window is 112 centimeters, find the total area of the window.
:
h = the height of the rectangular portion of the window
The perimeter = 1/2 the circumference + twice the height + the base
(1%2F2*pi%2A112) + 2h + 112 = 1512
351.858 + 112 + 2h = 1512
463.858 + 2h = 1512
2h = 1512 - 463.858
2h = 1048.142
h = 1048/2
h = 524.071 cm is the height
:
total area; semicircle radius: 112/2 = 56 cm
A = 1%2F2*pi%2A56%5E2 + (524.071*56)
A = 4926.017 + 29348.144
A = 34,274.161 sq/cm

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
A Norman window has the shape of a rectangle surmounted by a semicircle. If the perimeter of the window is 1512 centimeters and the length of the base of the window is 112 centimeters, find the total area of the window.
area=cm^2


Thank you for the help!
Height of rectangular section: 612.035 cm

Length of base: 112 cm

Area of semi-circle: 

Area of window: