SOLUTION: I want to cover a roughly rectangular area w netting. The height is 9 feet(but one side is along a solid fence, so could be 4 feet), two sides are each 6 feet, and the other side

Algebra ->  Surface-area -> SOLUTION: I want to cover a roughly rectangular area w netting. The height is 9 feet(but one side is along a solid fence, so could be 4 feet), two sides are each 6 feet, and the other side      Log On


   

Question 1076809: I want to cover a roughly rectangular area w netting. The height is 9 feet(but one side is along a solid fence, so could be 4 feet), two sides are each 6 feet, and the other side is 5 1/2 feet. How much netting do I need? Netting comes as a rectangular or square piece.
Thank you.
Answer by rapture(86) About Me  (Show Source):
You can put this solution on YOUR website!
What do you mean it could be 4 feet?


Is it 9 feet or 4 feet?


Let A = rectangular surface area


Use the formula: A = 2(wh + Lh + Lh)


Rewrite 5_1/2 as 11/2 for easy calculation.


If the height is 9 feet, use the following set up:


A = 2[(11/2)(9) + (6)(9) + (6)(9)]


If the height is 4 feet, use the following set up:


A = 2[(4)(9) + (6)(9) + (6)(9)]


You finish.