SOLUTION: Consider a square with side of length​ s, diagonal of length​ d, perimeter P and area A.
Write P as a function of s in simplified form.
Algebra ->
Surface-area
-> SOLUTION: Consider a square with side of length​ s, diagonal of length​ d, perimeter P and area A.
Write P as a function of s in simplified form.
Log On
Question 1065281: Consider a square with side of length s, diagonal of length d, perimeter P and area A.
Write P as a function of s in simplified form. Found 2 solutions by Alan3354, Boreal:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! As I see this, P=4s
the diagonal forms 2 right triangles.
d^2=2s^2
The area is s^2, the simplest way to do it.
That is (0.5 d^2), but they don't want the area as f(diagonal) only as f(s)