SOLUTION: A regular 16-gon is inscribed inside a circle, as shown in the figure. Sixteen congruent isosceles triangles are created by connecting the center of the circle to each vertex of th

Algebra ->  Surface-area -> SOLUTION: A regular 16-gon is inscribed inside a circle, as shown in the figure. Sixteen congruent isosceles triangles are created by connecting the center of the circle to each vertex of th      Log On


   

Question 1062789: A regular 16-gon is inscribed inside a circle, as shown in the figure. Sixteen congruent isosceles triangles are created by connecting the center of the circle to each vertex of the 16-gon. The base length of one of the isosceles triangles is b, and the height is h.
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What is the area of the 16-gon?
A16-gon= __________ 1/2bh
*[illustration decagon.png]
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

1/2bh is the area of one of those triangles,

So multiply it by 16 and you'll have the area of all 16
triangles, which is 

16 × 1/2bh and since half of 16 is 8, the answer is

8bh.

Edwin