SOLUTION: Compute for the value of {{{int(int((1/(1+4x^2+9Y^2)^2), dx,-infinity, infinity),dy, -infinity, infinity)}}}

Algebra ->  Surface-area -> SOLUTION: Compute for the value of {{{int(int((1/(1+4x^2+9Y^2)^2), dx,-infinity, infinity),dy, -infinity, infinity)}}}      Log On


   



Question 1062026: Compute for the value of

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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Compute for the value of

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1.  Let me show first how to calculate more simple integral 


    .      (1)


    Change variables for polar coordinates x = r%2Acos%28phi%29,  y = r%2Asin%28phi%29.

    Then dx*dy = r%2Adr%2Ad%28phi%29, and the integral (1) becomes 

     =  = (introduce new variable z = r%5E2) = .


    The internal integral is 
                                                          |infinity
    int%28%281%2F%281%2B4z%29%5E2%29%2C+dz%2C0%2C+infinity%29 = %281%2F4%29%2A%28int%28%281%2F%281%2B4z%29%5E2%29%2C+d%284z%29%2C0%2C+infinity%29%29%29  = %28-1%2F4%29%2A%281%2F%281+%2B+4z%29%29 |         =  1%2F4.
                                                          |0

    Then the entire double integral (1) is  %281%2F2%29%2A%281%2F4%29%2A2pi = pi%2F4.



2.  Now, let us start with the original integral  

    .      (2)

To calculate this integral, let me introduce the new coordinate system 

   u = x,
   v = %283%2F2%29%2Ay.

Then

   x = u,  y = %282%2F3%29%2Av;  dx = du, dy = %282%2F3%29%2Adv, and the integral (2) becomes


   .

   The integral of "u" and "v" after the factor 2%2F3%29 was just calculated in the section #1.

   Hence, the final answer is %282%2F3%29%2A%28pi%2F4%29 = pi%2F6.

Answer. The integral (2) is equal to pi%2F6.