SOLUTION: The void cube is a 3 𠖧 cube with a hole through the centre of each face. If the side length of each small cube is 1 cm, what is the surface area in square cmon the void cube. Th

Algebra ->  Surface-area -> SOLUTION: The void cube is a 3 𠖧 cube with a hole through the centre of each face. If the side length of each small cube is 1 cm, what is the surface area in square cmon the void cube. Th      Log On


   



Question 1061895: The void cube is a 3 𠖧 cube with a hole through the centre of each face. If the side length of each small cube is 1 cm, what is the surface area in square cmon the void cube. Thanks
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The total of surface area (in square cm) on the void cube is highlight%2872%29 .

ONE APPROACH:
Let us start with a large cube made of 9 smaller cubes of side length 1cm .
After making the holes,
we end up with only the small cubes attached to the edges of the original large cube.
The large cube originally had (and ends up still having) 4%2B4%2B4=12 edges;
4 horizontal edges on the bottom base,
4 horizontal edges on the top base,
and 4 vertical connecting edges.
There were (and are) 4%2B4=8 vertices:
4 on the bottom base,
and 4on the top base.
On the void cube, each edge has
one central small cube, attached to 2 other cubes, with 6-2=4 faces exposed.
of the remaining small cubes on the edges, each one is on one of the 8 attached to 3 other small cubes, leaving 6-3=3 of its faces exposed.
There is a total of
12%2A4%2B8%2A3=48%2B24=highlight%2872%29 small cube face surfaces.

ANOTHER APPROACH:
Before making the holes, we had a large solid cube with edge length = 3cm .
Volume=%283cm%29%5E3=9cm%5E3 and surfacearea=6%283cm%29%5E2=6%289cm%5E2%29=54cm%5E2 for the solid cube.
We could start with a large solid cube made of 9 smaller 1cm%5E3 cubes,
looking like a Rubik cube.
From the large solid cube,
we first tunnel top to bottom through the middle of the top face,
removing 3 small cubes,
including the red%281%29 central core cube,
which in a Rubik cube would have no colored faces.
Then, back on our large holey cube,
we tunnel front to back from the front face,
this time removing only 3-red%281%29=2 more small cubes,
because the red%281%29 central core cube has been removed before.
Finally, we tunnel left to right from the left side through the large holey cube,
removing another 2 more small cubes.
We have removed 3%2B2%2B2=7 small cubes from the original large solid un-holey cube.
If we put back together the small cubes removed,
the same way they were attached to each other before,
we have something familiar anyone who ever took apart a Rubik cube.
There is a central core cube,
completely covered on all 6 faces by 6 other small cubes.
That is a total of red%286%29 small cube face surfaces removed from the original large cube.
Only 6-1=5 faces of those 6 small cubes are exposed
(the other one is attached to the central core cube).
Of those 5 exposed faces,
the 1 outermost face was the center of a face of the larger solid cube.
(If we started with a Rubik cube,
those 6 outermost faces,
1 face on each of 6 small cubes, are colored).
The other 5-1=4 faces on each of those still exposed 6 removed small cubes,
is a newly exposed surface.
That is a total of 6%2A4=green%2824%29 newly exposed small cube face surfaces.
Meanwhile, on the original cube, while converting it into the holey void cube,
we have removed red%286%29 small cube face surfaces,
and we have newly exposed green%2824%29 small cube face surfaces,
for a total of 54-red%286%29%2Bgreen%2824%29=highlight%2872%29 small cube face surfaces.