SOLUTION: A square area of edge a revolves about a line through one vertex, making and angle with an edge and not crossing the square.Show that the volume generated is pi a3(sin theta+ cos t
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-> SOLUTION: A square area of edge a revolves about a line through one vertex, making and angle with an edge and not crossing the square.Show that the volume generated is pi a3(sin theta+ cos t
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Question 1057706: A square area of edge a revolves about a line through one vertex, making and angle with an edge and not crossing the square.Show that the volume generated is pi a3(sin theta+ cos theta). Answer by Fombitz(32388) (Show Source):
