SOLUTION: The equations y = 2x - 1 and y = -1/2x + 4 intersect in Quadrant I. Find the area of the triangle formed with this point of intersection and the two y-intercepts of the lines.
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-> SOLUTION: The equations y = 2x - 1 and y = -1/2x + 4 intersect in Quadrant I. Find the area of the triangle formed with this point of intersection and the two y-intercepts of the lines.
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Question 1050683: The equations y = 2x - 1 and y = -1/2x + 4 intersect in Quadrant I. Find the area of the triangle formed with this point of intersection and the two y-intercepts of the lines. Found 3 solutions by ewatrrr, Fombitz, josmiceli:Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Graphically,
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The y intercepts are -1 and 4 respectively so the base of the triangle is
The height of the triangle is .
You can also find this using the intersection point of the two lines by setting them equal to each other,
So,
You can put this solution on YOUR website! Find the point of intersection
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By substitution:
Multiply both sides by
and
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The intersection is at ( 2,3 )
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Now find the y-intercepts
by setting
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( 0, -1 )
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( 0, 4 }
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The distance between the 2 y-intercepts is:
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The height of the triangle formed is
the x-value of the intersection ( 2,3 )
which is
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The area is 5 square units
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Here's the plot of the lines: