Question 1048269: A right triangle has one vertex on the graph of y=x^5 , x>0, at (x,y) another at the origin, and a third on the positive y-axis at (0,y). Express the area A of the triangle as a function of x
Found 2 solutions by MathLover1, advanced_Learner:
Answer by MathLover1(20850)   (Show Source):
You can put this solution on YOUR website! A right triangle has one vertex on the graph of  ,  , at ( , )
another at the origin, or ( ,)
and a third on the positive y-axis at (,)
remember, we let ; so, replace "" with  to get (,)
let's draw a picture:
since the point (,) is "" units to the  and "" units  , this means that the  of the triangle is "" units long and the  is "" units
So the base is " " and the height is 
Now recall (or look up), the area of any triangle is
 ..........substitute  and 
Answer by advanced_Learner(501)  (Show Source):
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