SOLUTION: Ref. Question 1046639: "(s + 5) (s - 4) = s^2 s^2 + s - 20 = s^2 s = 20ft for the Square" I don't understand these steps. Thanks.

Algebra ->  Surface-area -> SOLUTION: Ref. Question 1046639: "(s + 5) (s - 4) = s^2 s^2 + s - 20 = s^2 s = 20ft for the Square" I don't understand these steps. Thanks.      Log On


   



Question 1046667: Ref. Question 1046639:
"(s + 5) (s - 4) = s^2
s^2 + s - 20 = s^2
s = 20ft for the Square"
I don't understand these steps. Thanks.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

given:
A square garden is to be enlarged to a rectangular by adding 5ft, to the length and deducting 4ft.
the area will be unchanged
to find: present and new dimensions
as you know, the area of a square is
A=+length+%2A+width
Let s = side of square
so, the area is A=s%5E2........eq.1
now you want to make a rectangle from that square by adding 5ft to the s and the width reducing s by 4ft
so, rectangle will have:
the length: %28s+%2B+5%29
Width: %28s+-+4%29
the area of rectangle will be:
A=%28s+%2B+5%29+%28s+-+4%29...expand
+A=+s%2As+%2B+5%2As+-+s%2A4-5%2A4
A=+s%5E2+%2B+5s+-+4s-20
A=+s%5E2+%2B+s+-20.............eq.2
now we have:
A=s^2.............eq.1
A= s^2 + s -20.............eq.2
__________________________
since area is unchanged, left sides are equal; so, make equal right sides and solve for s
s%5E2=s%5E2+%2B+s+-20.....move all terms from right to the left
s%5E2-s%5E2+-+s+%2B20=0
-+s+%2B20=0
20=s+
s=20+
so, when we have square, side length is
s=20ft+ ->present dimensions

and area is A=20ft%2A20ft=400ft%5E2

when we make rectangle the length will be:
20ft%2B5ft=25ft and
the width will be 20ft-4ft=16ft

A=25ft%2A16ft=400ft%5E2