SOLUTION: How would I set up to figure the area of 560 sq ft with a length of 12 greater than the width's dimension. What are the dimensions?

Algebra ->  Surface-area -> SOLUTION: How would I set up to figure the area of 560 sq ft with a length of 12 greater than the width's dimension. What are the dimensions?      Log On


   

Question 104616: How would I set up to figure the area of 560 sq ft with a length of 12 greater than the width's dimension. What are the dimensions?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x=width, so x+12=length ... x(x+12)=560 ... x^2+12x=560

x^2+12x-560=0