SOLUTION: A frustrum of pyramid consist of square base of length 10cm and a top square of 7cm the heights of the frustrum is 6cm calculate (A) the surface area (B)volume

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Question 1043186: A frustrum of pyramid consist of square base of length 10cm and a top square of 7cm the heights of the frustrum is 6cm calculate
(A) the surface area
(B)volume

Answer by ikleyn(52786) About Me  (Show Source):
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A highlight%28cross%28frustrum%29%29 frustum of pyramid consists of square base of length 10 cm and a top square of 7 cm.
The heights of the highlight%28cross%28frustrum%29%29 frustum is 6 cm calculate
(A) the surface area
(B) volume
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Volume

See this Wikipedia article or this WEB-page.

The volume formula of a frustum of a square pyramid was introduced by the ancient Egyptian mathematics 
in what is called the Moscow Mathematical Papyrus, written ca. 1850 BC.:

V = %281%2F3%29%2Ah%2A%28a%5E2%2Bab%2Bb%5E2%29 

where a and b are the base and top side lengths of the truncated pyramid, and h is the height. 
The Egyptians knew the correct formula for obtaining the volume of a truncated square pyramid, 
but no proof of this equation is given in the Moscow papyrus.

By applying the formula,  we get   V = %281%2F3%29%2A6%2A%2810%5E2+%2B+10%2A7+%2B+7%5E2%29 = 438 cm%5E3.

By the way, the proof is easy.
As you know, the volume of the larger pyramid is  V%5B1%5D = %281%2F3%29%2Aa%5E2%2AH%5B1%5D, where H%5B1%5D is its height.
The volume of the smaller pyramid is  V%5B2%5D = %281%2F3%29%2Ab%5E2%2AH%5B2%5D, where H%5B2%5D is its height.

Obviously, from similarity H%5B1%5D = const%2Aa  and  H%5B2%5D = const%2Ab, where const is a constant value independent of "a" and "b".

Then  V%5B1%5D = %281%2F3%29%2Aconst%2Aa%5E3,  V%5B2%5D = %281%2F3%29%2Aconst%2Ab%5E3.

The volume of the frustum is the difference 

V = V%5B1%5D+-+V%5B2%5D = %281%2F3%29%2Aconst%2Aa%5E3+-+%281%2F3%29%2Aconst%2Ab%5E3%29 = %281%2F3%29%2Aconst%2A%28a%5E3+-+b%5E3%29 = %281%2F3%29%2Aconst%2A%28a-b%29%2A%28a%5E2+%2B+ab+%2B+b%5E2%29.

But const*(a-b) = H%5B1%5D-H%5B2%5D = h, the height of the frustum.

Therefore,  the volume of the frustum is  V = %281%2F3%29%2Ah%2A%28a%5E2%2Bab%2Bb%5E2%29.   QED.