SOLUTION: if a shapes area is 105 square cms and its perimeter is 52 cm what are the measure of the 2 dimensions

Algebra ->  Surface-area -> SOLUTION: if a shapes area is 105 square cms and its perimeter is 52 cm what are the measure of the 2 dimensions       Log On


   



Question 1039885: if a shapes area is 105 square cms and its perimeter is 52 cm what are the measure of the 2 dimensions

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
if a shapes area is 105 square cms and its perimeter is 52 cm what are the measure of the 2 dimensions
:
The area
L*W = 105
L = 105%2FW
:
The perimeter
2L + 2W = 52
simplify, divide by 2
L + W = 26
Replace L with 105%2FW
105%2FW + W = 26
multiply by W to get rid of the denominator
105 + W^2 = 26W
A quadratic equation
W^2 - 26W + 105 = 0
You can use the quadratic formula, but this will factor to:
(W-21)(W-5) = 0
Two solutions
W = 21 is the width, then 5 = the length
W = 5 is the width, then 21 = the length
:
You can confirm this, find the perimeter with these values