SOLUTION: Lauren has a dog named Sammy tied to the corner of her garage with the dimensions of 50 ft by 40 ft. Sammy is tied to a leash that is 48 ft. How much area can the dog access?
Algebra ->
Surface-area
-> SOLUTION: Lauren has a dog named Sammy tied to the corner of her garage with the dimensions of 50 ft by 40 ft. Sammy is tied to a leash that is 48 ft. How much area can the dog access?
Log On
Question 1033238: Lauren has a dog named Sammy tied to the corner of her garage with the dimensions of 50 ft by 40 ft. Sammy is tied to a leash that is 48 ft. How much area can the dog access? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Lauren has a dog named Sammy tied to the corner of her garage with the dimensions of 50 ft by 40 ft. Sammy is tied to a leash that is 48 ft. How much area can the dog access?
----
Sketch the picture of a corner of the garage and 3/4 of a circle
with radius 48ft and center at the corner of the garage.
-------
Total area of the circle:: pi*48^2
------
Accessible area = (3/4)(pi)*48^2 = 5428.67 sq.ft.
---------------
Cheers,
Stan H.
---------------