SOLUTION: A retangular piece of sheet iron 625 cm in area is rolled to form a cylinder 9 cm in dameter. find the height and volume of this cylinder.

Algebra ->  Surface-area -> SOLUTION: A retangular piece of sheet iron 625 cm in area is rolled to form a cylinder 9 cm in dameter. find the height and volume of this cylinder.      Log On


   



Question 1009591: A retangular piece of sheet iron 625 cm in area is rolled to form a cylinder 9 cm in dameter. find the height and volume of this cylinder.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
The length (L) of the rectangle is the
circumference of the cylinder.
.
circumference=%28pi%29%28diameter%29
L=%28pi%29%289cm%29
L=28.27cm
.
(For area I assume you meant 625 square centimeters)
W=width of rectangle=height of cylinder
.
Area=%28L%29%28W%29
625cm%5E2=%2828.27cm%29%28W%29
625cm%5E2%2F28.27cm=W
22.11cm=W
.
The height (H) of the cylinder is 22.11cm,
the radius (R) is 4.5cm
V=volume of cylinder
.
V=pi%28R%5E2%29H
V=pi%284.5cm%29%5E2%2822.11cm%29
V=pi%2820.25cm%5E2%29%2822.11cm%29
V=pi%28447.73cm%5E3%29
V=1406.58cm%5E3
.
ANSWER: The height of the cylinder is 22.11cm,
and the volume is 1406.58 cubic centimeters.