SOLUTION: what is the area and perimeter of a ice cream cone shape object when the width given is 6m and the length given is 6m?

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Question 1008121: what is the area and perimeter of a ice cream cone shape object when the width given is 6m and the length given is 6m?

Found 2 solutions by josgarithmetic, Master Singleton:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
How do you mean for perimeter about this three dimensional form? What kind of "width"? Maybe recheck your problem description.

Answer by Master Singleton(1) About Me  (Show Source):
You can put this solution on YOUR website!
So your question "what is the area and perimeter of a ice cream cone shape object when the width given is 6m and the length given is 6m?" is a bit vague but from my perspective do you mean "the width given" as "the diameter given" of the semi-circle and as "the base of the triangle given" is 6 meters and "the height given" as "the height given" of the triangle is 6 meters? Also do you mean this shape shown below?

If yes then to find the area of a semi-circle:
Firstly find the radius of the semi-circle +radius+=+0.5%2A6+=+3+ then sub 3 into the area of semi-circle formula +A+=%280.5%2Api%29%2Aradius%5E2+ which looks like this +A+=%280.5%2Api%29%2A3%5E2+ which then equates to +1.570796327%2A9+ and finally +A+=+14.13716694m%5E2+
Then to find the area of a triangle:
Firstly sub both 6's into +A+=+%280.5%2Abase%29%2Aheight+ which looks like this +A+=+%280.5%2A6%29%2A6+ which equates to +3%2A6+ and finally +A+=18m%5E2+
Then find the sum of the area of a triangle and the area of a semi-circle:
+A+=+14.13716694m%5E2+%2B+18m%5E2+ which equates to +A+=+32.13716694m%5E2+


To find the perimeter first find the hypotenuse of the triangle:
first sub 3 and 6 into +Hypotenuse%5E2+=+base%5E2%2Bheight%5E2+ which looks like this +Hypotenuse%5E2+=+3%5E2%2B6%5E2+ which equates to +Hypotenuse+=+sqrt%2845%29+ and finally +Hypotenuse+=+6.708203932m+
secondly find the arc of the semi-circle:
first sub 6 into +Arc++=+%280.5pi%29%2Adiameter+ which looks like this +Arc++=+%280.5pi%29%2A6+ which equates to +Arc++=+1.570796327%2A6+ and finally +Arc++=+9.424777961m+
finally find the sum of the hypotenuses and the arc of the semi-circle to find the perimeter:
+P++=+%286.708203932%2A2%29%2B9.424777961+ which equates to +P+=+22.84118582m+

Therefore the area of the cone is +32.13716694m%5E2+ and the perimeter of the cone is +22.84118582m+