SOLUTION: a wire cross section diameter decresed 5% then volumes equal which percentage length increased

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Question 1006486: a wire cross section diameter decresed 5% then volumes equal which percentage length increased

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
If the diameter decreases by %225%25%22 ,
it becomes %22100%25%22-%225%25%22=%2295%25%22=95%2F100=0.95 of the original diameter.
As a consequence, the cross-section surface area,
area=pi%2Adiameter%5E2%2F4 ,
becomes
.
It becomes 0.9025=90.25%2F100=%2290.25%25%22 of the original cross-section surface area.
As the wire can be considered a cylinder,
with a base the same size/shape as the circular cross-section,
and the length of the wire for a height,
the original wire's volume is
volume=area%2Alength .
The new wire's volume is
new_volume=new_area%2Anew_length=0.9025%2Aarea%2Anew_length .
Since that volume has to be the same,
0.9025%2Aarea%2Anew_length=area%2Alength-->0.9025%2Anew_length=length-->new_length=length%2F0.9025
The relative change in length is
%28rounded%29=10.8033%2F100%28rounded%29=%2210.8033%25%22%28rounded%29 .
We cannot give an exact decimal value,
we have to give a rounded, approximate result,
as %2210.8%25%22 , or %2211%25%22 , for example,
because 1%2F0.9025 and 1%2F0.9025-1 written as decimals would have an infinite number of digits.
Since we start with two significant figure in %2295%25%22,
reporting the result as %2210.8%25%22 (very similar precision),
or %2211%25%22 (same number of significant digits) makes sense.

NOTE:
If all that talk about precision and significant figures, doesn't make sense to you, pretend that I did not write that.