Solver Finding area of a circle
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==section input The radius,r, of a circle is *[input r=5] ==section solution The formula for finding the area of a circle is {{{A=pi(r^2)}}} Since the radius is $r, we can plug in $r for the radius. So {{{A=pi($r^2)}}} Replace pi with 3.14159 because those are the first 5 decimal digits for pi. {{{A=3.14159($r^2)}}} *[assign r2=($r)^2] {{{A=3.14159($r2)}}} *[assign r3=$r2*3.14159] {{{highlight(A=$r3)}}} The area is roughly $r3 units^2. ==section output r2,r3 ==section check
