Question 1208142: If every element of a set A is also an element of a set B, then we say that A is a subset of B and write A ⊆ B.
Sample 1
Set A = { x, y, z }
Set B = { w, x, y, z }
I can say that A ⊆ B.
Sample 2
Set A = { 1, 2, 3 }
Set B = { 0, 1, 2, 3, 4, 5 }
I can say that A ⊆ B.
You say?
Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
If every element of a set A is also an element of a set B, then we say that A is a subset of B and write A ⊆ B.
Sample 1
Set A = { x, y, z }
Set B = { w, x, y, z }
I can say that A ⊆ B.
Sample 2
Set A = { 1, 2, 3 }
Set B = { 0, 1, 2, 3, 4, 5 }
I can say that A ⊆ B.
You say?
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(1) Your answer in part (1) is correct.
(2) Your answer in part (2) is correct.
Answer by math_tutor2020(3817)  (Show Source):
You can put this solution on YOUR website!
Both of your answers are correct.
It might help to highlight the items of interest.
A = { x, y, z }
B = { w, x, y, z }
which helps confirm that A is indeed a subset of B.
Anything inside set A is also in set B (but not vice versa).
Also,
A = { 1, 2, 3 }
B = { 0, 1, 2, 3, 4, 5 }
which is another scenario when A is a subset of B.
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Let's look at another example
A = {1,2,3}
B = {1,2,4,5,6}
Highlight everything in set A. Mark those items in set B (if they exist).
A = {1,2,3}
B = {1,2,4,5,6}
Unfortunately the element "3" is not found in set B, so set A isn't a subset of B.
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