SOLUTION: if A= {42,45,48,...,75}, how many subsets does A have ?
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Question 1019194
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if A= {42,45,48,...,75}, how many subsets does A have ?
Answer by
richard1234(7193)
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Assuming all of the numbers in A are in arithmetic sequence, A has ((75-42)/3) + 1 = 12 elements. The number of subsets of A is 2^12 = 4096.