SOLUTION: Solve this problem algebraically: fourth root (x^2 + 16x) = 2

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Question 99647: Solve this problem algebraically:
fourth root (x^2 + 16x) = 2
Found 2 solutions by scott8148, checkley71:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+16x=2^4 ... x^2+16x-16=0 ... x=%28-16+%2B-+sqrt%2816%5E2-4%2A1%2A%28-16%29%29%29%2F%282%2A1%29 ... x=%28-16+%2B-+sqrt%2864%2A5%29%29%2F2

x=-8+%2B-+4sqrt%285%29

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+16x=2
x^2+16x-2=0
using the quadratic equation:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
we get:
X=(-16+-SQRT[16^16-4*1*-2])/2*1
X=(-16+-SQRT256+8])/2
X=(-16+-SQRT264)/2
X=(-16+-16.248)/2
X=-16+16.248)/2
X=.248/2
X=.124 ANSWER.
X=(-16-16.248)/2
X=-32.248/2
X=-16.124 ANSWER.