SOLUTION: I need help completing the square for this problem. 16x^2-16x-5=0 So far I have tried this: 16x^2-16x+[1/2(-16)]=5+[1/2(-16)] 16x^2-16x+64=5+64 16(x^2-x+4)=69 16(????

Algebra ->  Square-cubic-other-roots -> SOLUTION: I need help completing the square for this problem. 16x^2-16x-5=0 So far I have tried this: 16x^2-16x+[1/2(-16)]=5+[1/2(-16)] 16x^2-16x+64=5+64 16(x^2-x+4)=69 16(????      Log On


   

Question 97658: I need help completing the square for this problem.
16x^2-16x-5=0

So far I have tried this:
16x^2-16x+[1/2(-16)]=5+[1/2(-16)]
16x^2-16x+64=5+64
16(x^2-x+4)=69
16(????????????

I'm lost from this point on. I tried factoring but it's not working for me. I hope you can help me.
Thank you very much
Solve a Quadratic Equation by completing the square.
I was not sure what would be an acceptable answer for your teacher so I worked it all the way out. This problem is a Quadratic Equation. Here is your solution.
Found 2 solutions by Msgenes, MathTherapy:
Answer by Msgenes(10) About Me  (Show Source):
You can put this solution on YOUR website!
Solve a Quadratic Equation by completing the square.
I was not sure what would be an acceptable answer for your teacher so I worked it all the way out. This problem is a Quadratic Equation. Here is your solution.

16x^2-16x-5=0
(16x^2-16-5)/16=0
x^2-1x-5/16=0
x^2-1x-5/16+5/16=0+5/16
x^2-1x=5/16
( -1/2)^2=1/4
x^2-1x+1/4=5/16+1/4(4/4)
(x-1/2)^2=5/16+4/16
(x-1/2)^2=9/16
Sqrt(x-1/2)^2 )= Sqrt(9/16)
x-1/2=3/4
x=1/2±3/4(If this is not your final solution according to your teacher, finished solution continues below)
x-1/2+1/2=3/4+1/2(2/2)
x=3/4+2/4
x=5/4
x-1/2=-3/4
x-1/2+1/2=1/2(2/2)-3/4
x=2/4-3/4
x=-1/4
Good Luck. :)

Answer by MathTherapy(10801) About Me  (Show Source):
You can put this solution on YOUR website!
I need help completing the square for this problem.

16x^2-16x-5=0

So far I have tried this:

16x^2-16x+[1/2(-16)]=5+[1/2(-16)]
16x^2-16x+64=5+64
16(x^2-x+4)=69
16(????????????
 
I'm lost from this point on. I tried factoring but it's not working for me. I hope you can help me.

Thank you very much

Solve a Quadratic Equation by completing the square. 

I was not sure what would be an acceptable answer for your teacher so I worked it all the way out.
This problem is a Quadratic Equation. Here is your solution.
***********************************************************
You would be lost, because you should've FIRST divided through, by 16, in order to make the coefficient on x%5E2, 1.
16x%5E2+-+16x+-+5+=+0
This quadratic can be solved by FACTORING. Often-times, this author will solve, by FACTORING, if possible, 
before or after completing the square, and then match the solutions. You can do the same, if you wish!

           16x%5E2+-+16x+-+5+=+0
         16x%5E2%2F16+-+16x%2F16+-+5%2F16+=+0%2F16----- Dividing each side by 16
                 x%5E2+-+x+-+5%2F16+=+0 
                         x%5E2+-+x+=+5%2F16 ----- Adding 5%2F16 to both sides
x%5E2+-+x+%2B+%28%281%2F2%29%28-+1%29%29%5E2+=+5%2F16+%2B+%28%281%2F2%29%28-+1%29%29%5E2 ---- Squaring 1%2F2 of b, then adding result to both sides
          x%5E2+-+x+%2B+%28-+1%2F2%29%5E2+=+5%2F16+%2B+%28-+1%2F2%29%5E2 
                    %28x+-+1%2F2%29%5E2+=+5%2F16+%2B+1%2F4 
                   %28x+-+1%2F2%29%5E2+=+5%2F16+%2B+4%2F16 
                  %28x+-+1%2F2%29%5E2+=+9%2F16 
            sqrt%28%28x+-+1%2F2%29%5E2%29+=+0+%2B-+sqrt%289%2F16%29 ---- Taking square root on both sides
                       x+-+1%2F2+=+0+%2B-+3%2F4 
                            x+=+1%2F2+%2B-+3%2F4
                            x+=+2%2F4+%2B-+3%2F4