SOLUTION: solve for v, where v is a real number ^4√2v+2 +1=3 Hint: There may be no solution or more than one solution,if so use commas

Algebra ->  Square-cubic-other-roots -> SOLUTION: solve for v, where v is a real number ^4√2v+2 +1=3 Hint: There may be no solution or more than one solution,if so use commas      Log On


   

Question 951576: solve for v, where v is a real number
^4√2v+2 +1=3
Hint: There may be no solution or more than one solution,if so use commas
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
solve for v, where v is a real number
^4√2v+2 +1=3
Assume it's
4sqrt%282v%2B2%29+%2B+1+=+3
subtract 1 from both sides
4sqrt%282v%2B2%29+=+2
raise both sides to the 4th power
2v + 2 = 2^4
2v + 2 = 16
2v = 16 - 2
2v = 14
v = 14/2
v = 7
:
:
Check this on your calc, enter (2(7)+2)^(1/4) + 1