SOLUTION: I am having trouble solving this problem. sqrt(x+2)(x-6)=x-5.....the (x+2) and (x-6) are both under the same square root.

Algebra ->  Square-cubic-other-roots -> SOLUTION: I am having trouble solving this problem. sqrt(x+2)(x-6)=x-5.....the (x+2) and (x-6) are both under the same square root.      Log On


   

Question 927348: I am having trouble solving this problem. sqrt(x+2)(x-6)=x-5.....the (x+2) and (x-6) are both under the same square root.
Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28%28x%2B2%29%2A%28x-6%29%29=x-5
squaring on both sides
%28sqrt%28%28x%2B2%29%2A%28x-6%29%29%29%5E2=%28x-5%29%5E2
%28x%2B2%29%2A%28x-6%29=%28x-5%29%5E2
x%28x-6%29%2B2%28x-6%29+=%28x-5%29%2A%28x-5%29
+x%5E2-6x%2B2x-12=+x%28x-5%29-5%28x-5%29
+x%5E2-4x-12+=x%5E2-5x-5x%2B25
+x%5E2-4x-12+=x%5E2-10x%2B25
move x^2-10x+25 to the right
x%5E2-4x-12+-x%5E2%2B10x-25=0
6x-37=0
move -37 to the right
+6x=+37
divide with 6 on both sides
+6x%2F6++=+37%2F6
+x=+37%2F6