You can put this solution on YOUR website!
Square both sides of the equation:
Put the equation in standard form:
Factor:
Equate each factor to 0 and solve for x:
Now, you need to plug these results back into the original equation to see if it still holds true. You can see that x=2 is a valid answer, since the equation holds when you plug that one in. However, x=-1 does not hold true. That is called an "extraneous root." It's a result of solving the problem, but it is not a valid answer. The only correct answer is:
Good Luck,
tutor_paul@yahoo.com